|  |  GeoAstro Applets |  Astronomy |  Chaos Game |  Java |  Miscel- laneous | 
| The
                only tools required by Kumar's technique are a sheet of
                graph paper, and a setsquare (or a 45° right triangle).  x2 + px + q = 0 - Plot the
                    point (q,p). - Place the setsquare ABC: with its edge AC passing through the point (1,0) on the horizontal axis, with its apex A on the vertical axis, with the perpendicular edge AB passing through the point (q,p). - The ordinate of the point A on the vertical axis gives the negative value of one of the roots. Quadratic
                      equation: x2 + px + q = 0 Example:
                      p=3, q=2, The proof is given in the paper of Arun Kumar. roots: x1=-1, x2=-2 | |
|  | Checking the box will
                mark certain values q, and p: - q, and p are a multiple of the raster size, and - the roots x1 and x2 (if any) are multiples of the raster size. | 
|  | Select the
                raster size, or a continuous mode ("Raster off"). A table of p, q, x1, x2 is available by "Data Window". | 
| The curve p = 2·sqrt(q)
                  represents the limit between the regions of (p,q) with
                  reals roots existing and no real roots. It corresponds
                  to the discriminant D = sqrt(p2/4 - q) = 0. | |
