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            Where
            is the missing energy ?
            
            A capacitor (capacity C) is charged at the voltage U
            
              
            
            and then disconnected from the power supply. It
            contains the electric charge Q = C·U and the energy
            W = 0.5·C·U2.
            
              
            
            Now, the capacitor is connected (parallel) to the same
            uncharged capacitor (total capacity now C+C=2·C),
            and the voltage will drop to U1 = Q /
            (2·C) = U / 2.
            
              
            
            Each of the capacitors has the energy W1 =
            0.5·C·(U/2)2 = W / 4 and both
            capacitors together have the energy W2 =
            2·W1 = W / 2, which is
            half of the energy W at
            start, even if the wires are very thick and have very
            little resistance.
            
             Where is the missing energy
            ???
            
             
            
            
            
            
              
            
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